![]() If the certain process requires more time than the remaining lifetime of CPU then don't process this and terminate the scheduler Initialize the scheduler with 3 processesĪssign random burst time and serving time for each process in such a way that the process generation time gap keeps on increasing The program outputs in the form of a ghantt chart. If a job does not finish in its allotted time, it is moved to the "back" of the list (this is done by simply moving the current reference ahead in the list by one node). Whenever a job finishes, it is simply removed from the list. Any new job is added to the "back" of the list (the spot directly proceeding the job currently being run). One of the best ways to implement this policy is through the use of a circular linked list. This policy is very fair and very easy to implement. If the process does not finish, it goes to the end of the line and the next process gets to run. This simply means that each process gets to run for a set amount of time. For this project, we will assume a very simple round-robin scheduler. This process can actually become quite involved. One of the most basic functions of an operating system is to schedule these processes. In modern computer systems, it is common for users to have many programs running at one time. ![]() ![]() Java Program to simulate the working of the round robin scheduling algorithm. ![]()
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